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A student was given an assignment to show that 2 = 1. He successfully showed this using the argument below.
PROOF
Let a, b be real numbers, such that
a = b = 1
Then,
a^2 = ab
a^2 - b^2 = ab - b^2
(a-b) (a+b) = b(a-b)
This imply,
(a+b) = b
Since a=b=1
Hence,
2 = 1 QED.
An alternative proof is;
For any x real number,
x^2 = x^2
x^2 - x^2 = x^2 -x^2
x(x - x) = (x -x)(x + x)
This imply
x = x + x
x = 2x
Hence, 1 = 2 QED.
REMARK
There is something wrong with these proofs. kindly spot out the line where the argument has a flaw.
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